Questions & explanations
1. Set A consists of the numbers {2, 5, x, 9, 11, y}, where x and y are positive integers. If the median of the set is 7, and x < y, what is the value of x?
- 3
- 5
- 6
- 7
- 8
Answer: 5
Sorted order: 2,5,x,9,11,y (since x<y and x<9, y>11? y could be >11 or between 9 and 11). With 6 numbers, median is average of 3rd and 4th. For median 7, (x+9)/2=7 → x+9=14 → x=5. Then y must be >9? if x=5, sorted: 2,5,5,9,11,y. Median = (5+9)/2=7. y can be any >9, condition x<y holds.
2. Which of the following best describes the standard deviation of a set of numbers?
- The average of the numbers in the set
- The difference between the largest and smallest numbers
- A measure of how spread out the numbers are from the mean
- The middle value when the numbers are arranged in order
- The number that appears most frequently
Answer: A measure of how spread out the numbers are from the mean
Standard deviation quantifies the dispersion of data points around the mean. A small standard deviation indicates data points are close to the mean, while a large one indicates they are spread out. Option c correctly defines it as a measure of spread from the mean.
3. Data set A: {10, 20, 30, 40, 50}. Data set B: {15, 20, 25, 30, 35}. Which of the following is true about the standard deviations of the two sets?
- Standard deviation of A is greater than that of B.
- Standard deviation of B is greater than that of A.
- The standard deviations are equal.
- Standard deviation of A is twice that of B.
- Cannot be determined from the information given.
Answer: Standard deviation of A is greater than that of B.
Set A has values spread from 10 to 50 (range 40), while set B is from 15 to 35 (range 20). Since the values in A are more spread out from the mean (30), its standard deviation is larger. No calculation needed; visual spread indicates greater SD.
4. The following data set shows the number of books read by students in a month: 2, 3, 3, 5, 5, 5, 7, 7, 8, 8, 8, 9. What is the mode of the data set?
- 5 only
- 8 only
- 5 and 8
- 3, 5, and 8
- No mode
Answer: 5 and 8
Count frequencies: 2 appears once, 3 appears twice, 5 appears three times, 7 appears twice, 8 appears three times, 9 appears once. The highest frequency is 3, occurring for both 5 and 8. Thus the data set is multimodal with modes 5 and 8.
5. Data set A: {10, 10, 10, 10, 10}. Data set B: {5, 5, 10, 15, 15}. Which statement is true?
- Set A has a larger standard deviation than set B.
- Set B has a larger standard deviation than set A.
- Both sets have the same standard deviation.
- Set A has a standard deviation of 10.
- Set B has a standard deviation of 0.
Answer: Set B has a larger standard deviation than set A.
Set A has all values equal to the mean (10), so standard deviation is 0. Set B has values spread from 5 to 15, so its standard deviation is greater than 0. Thus, set B has a larger standard deviation.
6. Data set S consists of the numbers {2, 2, 2, 5, 5, 5, 5, 5, 5, 5}. Which of the following is true about the standard deviation of S?
- It is 0 because there are repeated values.
- It is less than the standard deviation of {2, 5}.
- It is greater than the standard deviation of {2, 5}.
- It is equal to the standard deviation of {2, 5}.
- It cannot be determined without knowing the exact values.
Answer: It is less than the standard deviation of {2, 5}.
Standard deviation measures spread. Set S has many 5's and few 2's, so the mean is closer to 5, reducing spread compared to {2,5} which has equal frequency and mean 3.5. Thus SD of S is smaller.
7. A data set consists of the following numbers: 3, 7, 9, 12, 15, 18, 21. If the number 10 is added to the set, what is the median of the new set?
- 10
- 11
- 12
- 13
- 14
Answer: 11
Original set (odd count 7): sorted 3,7,9,12,15,18,21; median = 12. Adding 10 gives 8 numbers (even). New sorted: 3,7,9,10,12,15,18,21. Median = average of 4th and 5th = (10+12)/2 = 11.
8. A store sells two types of coffee: Type A at $12 per pound and Type B at $18 per pound. How many pounds of Type A must be mixed with 10 pounds of Type B to create a blend that costs $15 per pound?
- 5
- 10
- 12
- 15
- 20
Answer: 10
Let x = pounds of Type A. Total cost = 12x + 18(10) = 12x + 180. Total weight = x + 10. Average cost = (12x + 180)/(x + 10) = 15. Multiply: 12x + 180 = 15x + 150 → 30 = 3x → x = 10.
9. A company has two departments: Sales and Marketing. The Sales department has 40 employees with an average salary of $50,000. The Marketing department has 60 employees with an average salary of $70,000. What is the weighted average salary of all employees in the company, using the percentages of employees as weights?
- $58,000
- $60,000
- $62,000
- $64,000
- $66,000
Answer: $62,000
Total employees = 40+60 = 100. Sales weight = 40/100 = 0.4, Marketing weight = 60/100 = 0.6. Weighted average = (0.4 × 50,000) + (0.6 × 70,000) = 20,000 + 42,000 = $62,000.
10. A company has three departments: A with 10 employees averaging $50,000 salary, B with 20 employees averaging $60,000, and C with 30 employees averaging $70,000. What is the average salary across all departments?
- $60,000
- $62,500
- $63,333
- $65,000
- $66,667
Answer: $63,333
Total salary = 10×50000 + 20×60000 + 30×70000 = 500000 + 1200000 + 2100000 = 3,800,000. Total employees = 10+20+30 = 60. Average = 3,800,000 / 60 = 63,333.33 ≈ $63,333.
11. Class A has 20 students with an average score of 80. Class B has 30 students with an average score of 70. What is the overall average score for the two classes combined?
- 73
- 74
- 75
- 76
- 77
Answer: 74
Total points for class A = 20 × 80 = 1600. Total points for class B = 30 × 70 = 2100. Combined total = 3700. Combined students = 50. Overall average = 3700 / 50 = 74.
12. The standard deviation of a set of numbers is 5. If 10 is added to each number in the set, what is the new standard deviation?
- 5
- 10
- 15
- 50
- Cannot be determined
Answer: 5
Adding a constant to every value shifts the entire distribution but does not change the spread. Standard deviation measures dispersion, so it remains unchanged at 5.