p-Block (16) — NEET UG Questions

10 NEET UG practice questions on p-Block (16), part of Chemistry. Below are 10 of them in full, each with the answer and a written explanation.

Questions & explanations

1. Which of the following is an anomalous property of oxygen compared to other elements of Group 16?

  1. It has the largest atomic radius.
  2. It can show +6 oxidation state.
  3. It does not have d-orbitals to expand its octet.
  4. It exists as a solid at room temperature.

Answer: It does not have d-orbitals to expand its octet.

Oxygen, being in the second period, lacks d-orbitals. This prevents it from showing +6 oxidation state (unlike sulphur) and limits its covalency to 4. Option A is false (oxygen has smallest radius), B is false, D is false (oxygen is a gas).

2. The shape of the sulphur dioxide (SO₂) molecule is:

  1. Linear
  2. Trigonal planar
  3. Bent (V-shaped)
  4. Pyramidal

Answer: Bent (V-shaped)

SO₂ has sp² hybridisation with one lone pair of electrons on sulphur, giving a bent (V-shaped) geometry with an O–S–O bond angle of about 119°. Linear, trigonal planar, and pyramidal shapes do not match the electron pair geometry.

3. Which of the following statements about ozone (O₃) is correct?

  1. It is a linear molecule.
  2. It is paramagnetic.
  3. It is a powerful oxidising agent.
  4. It is stable at room temperature and does not decompose.

Answer: It is a powerful oxidising agent.

Ozone is a bent molecule (angular), diamagnetic, and decomposes readily to O₂. It is a strong oxidising agent (e.g., oxidises KI to I₂). Option A (linear) is wrong; B (paramagnetic) is false; D is false because ozone is unstable.

4. The highest oxidation state shown by sulphur in its compounds is:

  1. +4
  2. -2
  3. +6
  4. +7

Answer: +6

Sulphur has available 3d orbitals, allowing it to expand its octet and achieve a maximum oxidation state of +6 (e.g., in H₂SO₄). Option A (+4) and B (-2) are common but not the highest; +7 is not possible for sulphur.

5. The correct order of thermal stability of hydrides of Group 16 elements is:

  1. H₂O < H₂S < H₂Se < H₂Te
  2. H₂O > H₂S > H₂Se > H₂Te
  3. H₂O > H₂Se > H₂S > H₂Te
  4. H₂O = H₂S = H₂Se = H₂Te

Answer: H₂O > H₂S > H₂Se > H₂Te

Thermal stability of Group 16 hydrides decreases down the group because the bond dissociation energy decreases as the size of the central atom increases. Hence, H₂O is the most stable and H₂Te the least stable.

6. Which of the following oxoacids of sulphur contains a sulphur-sulphur (S–S) bond in its structure?

  1. Sulphuric acid (H₂SO₄)
  2. Sulphurous acid (H₂SO₃)
  3. Thiosulphuric acid (H₂S₂O₃)
  4. Pyrosulphuric acid (H₂S₂O₇)

Answer: Thiosulphuric acid (H₂S₂O₃)

Thiosulphuric acid (H₂S₂O₃) has a structure in which one sulphur atom is bonded to another sulphur atom (S–S bond). In contrast, H₂SO₄, H₂SO₃, and H₂S₂O₇ contain S–O–S or S=O bonds but no direct S–S linkage.

7. The general outer electronic configuration of elements of Group 16 (chalcogens) is:

  1. ns² np³
  2. ns² np⁴
  3. ns² np⁵
  4. ns² np⁶

Answer: ns² np⁴

Group 16 elements (O, S, Se, Te, Po) have six valence electrons, giving the configuration ns² np⁴. Option A is for Group 15, C for Group 17 (halogens), and D for Group 18 (noble gases).

8. Which of the following trends is correct for Group 16 elements (O, S, Se, Te, Po)?

  1. Atomic size decreases down the group.
  2. Ionisation enthalpy increases down the group.
  3. Electronegativity increases down the group.
  4. Atomic size increases down the group.

Answer: Atomic size increases down the group.

Down a group, new electron shells are added, so atomic size increases. Ionisation enthalpy and electronegativity generally decrease down the group. Thus, only option D is correct.

9. Which of the following is NOT an allotrope of sulphur?

  1. Rhombic sulphur
  2. Monoclinic sulphur
  3. Plastic sulphur
  4. Colloidal sulphur

Answer: Colloidal sulphur

Rhombic, monoclinic, and plastic (amorphous) sulphur are well-known allotropes. Colloidal sulphur is merely a finely divided form and not a distinct allotropic modification.

10. In the Contact process for the manufacture of sulphuric acid, the catalyst used for the oxidation of SO₂ to SO₃ is:

  1. V₂O₅
  2. Fe₂O₃
  3. MnO₂
  4. Al₂O₃

Answer: V₂O₅

Vanadium pentoxide (V₂O₅) is the catalyst employed in the Contact process to speed up the reaction: 2SO₂ + O₂ ⇌ 2SO₃. Fe₂O₃, MnO₂, and Al₂O₃ are not used for this purpose.

More Chemistry topics

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